3 Easy Steps to Graph 2nd Order LTI on Bode Plot

3 Easy Steps to Graph 2nd Order LTI on Bode Plot

Bode plots are graphical representations of the frequency response of a system. They’re used to research the soundness and efficiency of management programs, and to design filters and different sign processing circuits. Second-order linear time-invariant (LTI) programs are a standard sort of system that may be analyzed utilizing Bode plots. On this article, we’ll present you graph a second-order LTI system on a Bode plot.

To graph a second-order LTI system on a Bode plot, you have to to know the system’s pure frequency and damping ratio. The pure frequency is the frequency at which the system would oscillate if there have been no damping. The damping ratio is a measure of how rapidly the system’s oscillations decay. As soon as you already know the system’s pure frequency and damping ratio, you need to use the next steps to graph the system on a Bode plot:

1. Plot the system’s magnitude response. The magnitude response is the ratio of the output amplitude to the enter amplitude. For a second-order LTI system, the magnitude response is given by the next equation:

“`
|H(f)| = frac{1}{sqrt{1 + (2zeta f/ω_n)^2 + (f/ω_n)^4}}
“`

the place:

* f is the frequency
* ω_n is the pure frequency
* ζ is the damping ratio

2. Plot the system’s part response. The part response is the distinction between the output part and the enter part. For a second-order LTI system, the part response is given by the next equation:

“`
∠H(f) = -arctan(2ζ f/ω_n) – arctan(f/ω_n)^2
“`

How To Graph 2nd Order Lti On Bode Plot

A second-order linear time-invariant (LTI) system is a system that may be described by a second-order differential equation. The switch perform of a second-order LTI system is given by:

$$H(s) = frac{Ok omega_n^2}{s^2 + 2zeta omega_n s + omega_n^2}$$

the place:

* $Ok$ is the acquire of the system
* $omega_n$ is the pure frequency of the system
* $zeta$ is the damping ratio of the system

To graph the Bode plot of a second-order LTI system, we have to discover the magnitude and part of the switch perform at completely different frequencies.

Magnitude

The magnitude of the switch perform is given by:

$$|H(jomega)| = frac{Ok omega_n^2}{sqrt{(jomega)^2 + 2zeta omega_n jomega + omega_n^2}}$$

We will simplify this expression through the use of the next substitutions:

$$u = jomega$$

$$a = omega_n$$

$$b = 2zeta omega_n$$

This provides us:

$$|H(jomega)| = frac{Ok a^2}{sqrt{-u^2 + bu + a^2}}$$

We will now graph the magnitude of the switch perform by plotting $|H(jomega)|$ as a perform of $omega$.

Section

The part of the switch perform is given by:

$$angle H(jomega) = -arctanleft(frac{2zeta omega_n jomega}{omega_n^2 – j^2 omega^2}proper)$$

We will simplify this expression through the use of the next substitutions:

$$u = jomega$$

$$a = omega_n$$

$$b = 2zeta omega_n$$

This provides us:

$$angle H(jomega) = -arctanleft(frac{bu}{-a^2 – u^2}proper)$$

We will now graph the part of the switch perform by plotting $angle H(jomega)$ as a perform of $omega$.

Individuals Additionally Ask About How To Graph 2nd Order Lti On Bode Plot

What’s the distinction between a Bode plot and a Nyquist plot?

A Bode plot is a graphical illustration of the frequency response of a system. It reveals the magnitude and part of the system’s switch perform at completely different frequencies. A Nyquist plot is a graphical illustration of the system’s stability. It reveals the system’s poles and zeros within the advanced aircraft.

How can I take advantage of a Bode plot to design a filter?

A Bode plot can be utilized to design a filter by selecting the suitable cutoff frequencies and features. The cutoff frequencies are the frequencies at which the filter’s magnitude response drops by 3 dB. The features are the components by which the filter amplifies the sign at completely different frequencies.

What’s the relationship between the Bode plot and the Laplace remodel?

The Bode plot is said to the Laplace remodel by the next equation:

$$H(s) = mathcal{L}^{-1}left{H(jomega)proper}$$

the place:

* $H(s)$ is the Laplace remodel of the switch perform
* $H(jomega)$ is the frequency response of the switch perform